Руководство по PHP
Пред.	Глава 14. References Explained	След.

What References Are Not

As said before, references aren't pointers. That means, the following construct won't do what you expect:


<?php
function foo (&$var)
{
    $var =& $GLOBALS["baz"];
}
foo($bar); 
?>

What happens is that $var in foo will be bound with $bar in caller, but then it will be re-bound with $GLOBALS["baz"]. There's no way to bind $bar in the calling scope to something else using the reference mechanism, since $bar is not available in the function foo (it is represented by $var, but $var has only variable contents and not name-to-value binding in the calling symbol table).

Пред.	Начало	След.
What References Do	Уровень выше	Passing by Reference