->tableName() -- Get or set the table name of an object
Описание
Without any argument, it returns the table name that the object deals with. With a string, it will
set the table name for the instance of the object.
Заметка
Эта функция не должна вызываться статически.
Пример
Пример 34-1. getting and setting the tablename $person = new DataObjects_Person;
echo $person->tableName();
// echo's person
// now use the same object to query the extra_people table
$person->tableName('extra_people');
$person->id = 12;
$person->find(true);
// you can also use this in conjunction with table(), to create dataobjects for random tables..
$d = new DB_DataObject;
$d->tableName('person');
$d->table(array(
'id' => DB_DATAOBJECT_INT,
'name' => DB_DATAOBJECT_STRING,
));
$d->keys(array('id'));
$d->id = 12;
$d->find(true);
// should do the same as above..! |
|
HIVE: All information for read only. Please respect copyright! |
|
|
